(2x^2-x-3)-(x+1)=y

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Solution for (2x^2-x-3)-(x+1)=y equation:


Simplifying
(2x2 + -1x + -3) + -1(x + 1) = y

Reorder the terms:
(-3 + -1x + 2x2) + -1(x + 1) = y

Remove parenthesis around (-3 + -1x + 2x2)
-3 + -1x + 2x2 + -1(x + 1) = y

Reorder the terms:
-3 + -1x + 2x2 + -1(1 + x) = y
-3 + -1x + 2x2 + (1 * -1 + x * -1) = y
-3 + -1x + 2x2 + (-1 + -1x) = y

Reorder the terms:
-3 + -1 + -1x + -1x + 2x2 = y

Combine like terms: -3 + -1 = -4
-4 + -1x + -1x + 2x2 = y

Combine like terms: -1x + -1x = -2x
-4 + -2x + 2x2 = y

Solving
-4 + -2x + 2x2 = y

Solving for variable 'x'.

Combine like terms: y + -1y = 0
-4 + -2x + 2x2 + -1y = 0

The solution to this equation could not be determined.

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